z^3=(3-3i)/4

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Solution for z^3=(3-3i)/4 equation: 


x in (-oo:+oo)

z^3 = (3-(3*i))/4 // - (3-(3*i))/4

z^3-((3-(3*i))/4) = 0

z^3-((3-3*i)/4) = 0

(-1*(3-3*i))/4+z^3 = 0

(-1*(3-3*i))/4+(4*z^3)/4 = 0

4*z^3-1*(3-3*i) = 0

3*i+4*z^3-3 = 0

(3*i+4*z^3-3)/4 = 0

(3*i+4*z^3-3)/4 = 0 // * 4

3*i+4*z^3-3 = 0

x belongs to the empty set

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